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Node.js - File Upload

Updated: 2022-03-26

Background

Enctype

3 ways to encode HTML forms

  • application/x-www-form-urlencoded: default, more or less the same as a query string on the end of the URL.
  • multipart/form-data: if has file uploads(<input type="file">)
  • text/plain(Do NOT use)

Packages

  • body-parser: can parse bodies but NOT multipart bodies
// parse application/x-www-form-urlencoded
app.use(bodyParser.urlencoded({ extended: false }));

// parse application/json
app.use(bodyParser.json());
  • multer: handle multipart/form-data
var express = require('express');
var multer = require('multer');

var app = express();
app.use(multer({ dest: './uploads/' }));

Solution

HTML

<input id="file-upload" type="file" name="foo" />

Where id is used for jQuery selector to find this div, and “name” is used for looking for the file(there could be multiple files, identified by names).

Server

exports.uploadFile = function(req, res) {
    var html = fs.readFileSync(req.files.foo.path);
    // ...
    res.json({...});
}

req.files is a collection of files, if the filename is “foo”, then the info about this file is stored in req.files.foo, and req.files.foo.path is a local temporary path storing the uploaded file. Add the POST to app:

app.post('/uploadFile', yourModule.uploadFile);

Client(jQuery)

$('#btn-upload').click(function () {
  var data = new FormData();
  data.append('foo', $('#file-upload')[0].files[0]);

  $.ajax({
    url: '/uploadFile',
    type: 'POST',
    success: function (d) {
      console.log(d);
    },
    error: function () {
      console.log('error');
    },
    data: data,
    cache: false,
    contentType: false,
    processData: false,
  });
});

To get the file from the <input>, use $('#file-upload')[0].files[0]

The success callback will receive whatever the server returned.